P2 - naloga: izpis besed v okvirih; resitev Aljaz S.

Nalogo se da, kot velikansko vecino problemov v raculanistvu, resiti na vec nacinov;

import java.util.*;

class DN02 {
	public static void main(String[] args) {

        String[] l1 = new String[args.length];
        String[] l2 = new String[args.length];

        for(int i = 0; i < args.length; i++) {
            l2[i] = String.format("%s %s %s", (i % 2 == 0 ? "*" : "+"), args[i], (i % 2 == 0 ? "*" : "+"));
            String[] line = new String[l2[i].length()];
            Arrays.fill(line, i % 2 == 0 ? "*" : "+");
            l1[i] = String.join("", Arrays.asList(line));
        }

        System.out.println(String.join(" ", Arrays.asList(l1)));
        System.out.println(String.join(" ", Arrays.asList(l2)));
        System.out.println(String.join(" ", Arrays.asList(l1)));

	}
}

import java.util.*;

class DN02 {
	public static void main(String[] args) {

        String div = "";
        String mid = "";

        for(int i = 0; i < args.length; i++) {
            String c = i % 2 == 0 ? "*" : "+";
            String line = c + " " + args[i] + " " + c;
            mid += line + " ";
            div += c.repeat(line.length()) + " ";
        }

        System.out.println(div + "\n" + mid + "\n" + div);
	}
}

Seveda, se da tudi triktar loop-at skozi vse podane argumente, vsakic za eno vrstico. Predvidevam, da je vecina izbrala ta pristop.

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Zadnja posodobitev: April 5, 2022